# New Ticket Created by "Carl Mäsak"
# Please include the string: [perl #68528]
# in the subject line of all future correspondence about this issue.
# <URL: http://rt.perl.org/rt3/Ticket/Display.html?id=68528 >
<jnthn> rakudo: multi foo(:$a!, *%_) {}; multi foo(:$b, *%_) {}; foo(:a, :b)
<p6eval> rakudo 0d4fe0: OUTPUT«Ambiguous dispatch to multi 'foo'.
Ambiguous candidates had signatures::(Any :$a, Object *%_):(Any
:$b?, Object *%_)in Main (/tmp/1JICUeh8sD:2)»
[...]
<jnthn> So for tiebreaker
<jnthn> A the candidates are simply called in the order they were declared,
<jnthn> and the first one that successfully binds (and completes without
<jnthn> calling nextsame or nextwith) is considered the winner, and all the
<jnthn> other tied candidates are ignored.
[...]
<jnthn> If I understand S12 correctly, then by the spec the tie you
got earlier is a bug.
<jnthn> And the first candidate that appeared textually in your
program shoulda won.
