For the records: Now (post GLR) this gives List() -- which looks correct:
< bartolin> m: my $a = [ "this", "is", "so", "gross" ]; my $b = [ "that",
"is", "so", "funny" ]; my $c =
$b[2..3]; $a[3] = $c; say $a[3].WHAT # RT #76698
<+camelia> rakudo-moar 00be1e: OUTPUT«(Parcel)»
< GLRelia> rakudo-moar 467b79: OUTPUT«(List)»
But anyway, one way of setting $a to ["this", "is", "so", ["so", "funny"]]
would have been
$ perl6 -e 'my $a = [ "this", "is", "so", "gross" ]; my $b = [ "that", "is",
"so", "funny" ]; my $c = $b[2..3].Array; $a[3] = $c ; say $a.perl'
["this", "is", "so", ["so", "funny"]]
This also worked pre GLR -- the method Array was added back in 2011 with commit
0516515875.
I'm closing this ticket as 'resolved'. (No test added, since there doesn't seem
to be a bug involved.)
Finally, some further notes from IRC:
< ShimmerFairy> There was a Seq() way back when? Weeeeird O_o
< FROGGS> m: my $a = [ "this", "is", "so", "gross" ]; my $b = [ "that",
"is", "so", "funny" ]; my $c =
$b[2..3]; say $c.WHAT; $a[3] = $c; say $a[3].WHAT
<+camelia> rakudo-moar 00be1e: OUTPUT«(Parcel)(Parcel)»
< GLRelia> rakudo-moar 467b79: OUTPUT«(List)(List)»
< timotimo> "way back when"? at that time Seq didn't exist :)
< ShimmerFairy> timotimo: it's in that 2010 bug report though
< bartolin> ShimmerFairy: If you have looked at the ticket: I'm going to
close it, because I don't see a
bug there. At least nowadays one could use .Array if needed. Do
you agree?
< FROGGS> bartolin: it very much seems fixed
< ShimmerFairy> bartolin: not to mention GLR has thrown a wrench in any
list-related ticket :)
< bartolin> m: my $a = [ "this", "is", "so", "gross" ]; my $b = [ "that",
"is", "so", "funny" ]; my $c =
$b[2..3].Array; $a[3] = $c; say $a.perl
<+camelia> rakudo-moar 00be1e: OUTPUT«["this", "is", "so", ["so",
"funny"]]»
< GLRelia> rakudo-moar 467b79: OUTPUT«["this", "is", "so", ["so",
"funny"]]»
< FROGGS> a slice returns a list, and it stays a list, which is correct
