On Fri, Mar 25, 2005 at 03:47:43PM -0800, Greg Buchholz wrote:
:
: I'm wondering if the precedence of the "return" keyword isn't wrong
: in pugs. In the code below, fibo2 works as I'd expected, fibo returns
: nothing. (If this is expected behavior, I'd apppreciate someone
: pointing me to TFM).
:
: Thanks,
:
: Greg Buchholz
:
:
: #!perl6
: use v6;
:
: sub fib ($n) { return ($n<2) ?? 1 :: fib($n-2) + fib($n-1) }
: sub fib2 ($n) { return (($n<2) ?? 1 :: fib2($n-2) + fib2($n-1)) }
:
: my $x = fib(6);
: say " fib(6)=$x";
:
: my $y = fib2(6);
: say "fib2(6)=$y";
Both of those ought to work. I think return should parse like a list
operator, if it parses like anything else.
Larry
