# New Ticket Created by "Dave Whipp"
# Please include the string: [perl #61892]
# in the subject line of all future correspondence about this issue.
# <URL: http://rt.perl.org/rt3/Ticket/Display.html?id=61892 >
(rakudo 34751)
I've been trying to figure out how to do a "($hd, @tl) = @list" assignments.
./perl6 -e '
my @list = 1,2,3;
my ($hd, @tl) = @list;
say ([$hd], [...@tl]).perl
'
[[1], []]
That doesn't work, but it is possible by separating the declarations of "my
($hd, @tl)" to a separate statement:
./perl6 -e '
my @list = 1,2,3;
my ($hd, @tl);
($hd, @tl) = @list;
say ([$hd], [...@tl]).perl
'
[[1], [2, 3]]
BTW, in my various experiments to get this working, I found that flattening
the rvalue "($hd, @tl) = |@list" is an error (too many args to assignment)
-- I'm not sure that that is correct. Adding parens around the flattened
rvalue does work.
