[perl #72696] [BUG] Defining two different enumerations with the same enum value should result in ambiguity in Rakudo; doesn't

[Carl Mäsak]

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<masak> rakudo: enum A <a b c>; enum B <a b c>; say &a.perl
<p6eval> rakudo 1d4928: OUTPUT«B::a␤»
* masak submits rakudobug
<jnthn> ?
<jnthn> Heh
<moritz_> it should be ambiguous
<jnthn> Oh
<moritz_> I can never remember how to write that word :-)
<jnthn> Yeah, that.

According to S12:1787, rather than just picking B::a, &a should be
unavailable as a symbol, due to it being found both in A and in B.