[perl #69412] $*OUT.&printf not correctly declared

[Will Coleda via RT]

On Sat Sep 26 10:56:40 2009, dolmen wrote:
> Evaluation of $*OUT.&printf does not gives a result consistent with
> $*OUT.&say
> 
> <dolmen> rakudo: say $*OUT.&printf.WHAT;
> <p6eval> rakudo e33d20: OUTPUT«elements() not implemented in class
> 'Sub'␤in Main (/tmp/iPwK5u8ApO:0)␤»
> 
> <dolmen> rakudo: say $*OUT.&say.WHAT;
> <p6eval> rakudo e33d20: OUTPUT«IO()<0x2b0344268580>␤Bool()␤»
> <dolmen> rakudo: say &say.WHAT;
> <p6eval> rakudo e33d20: OUTPUT«␤»
> <dolmen> rakudo: $*OUT.printf("%05d", 5);
> <p6eval> rakudo e33d20: OUTPUT«00005»
> 
> --
> Olivier Mengué
> http://o.mengue.free.fr/

Note:

< sorear> say $*OUT.&say.WHAT  ===  say (say($*OUT)).WHAT

So that may not be quite what you're looking for, there (but the syntax 
you used does generate consistent results now also!). I assume you're 
wanting something more like:

< [Coke]> rakudo: say $*OUT.^methods.first('printf').WHAT
<+p6eval> rakudo 3fbd62: OUTPUT«Multi()␤»
< [Coke]> rakudo: say $*OUT.^methods.first('say').WHAT
<+p6eval> rakudo 3fbd62: OUTPUT«Multi()␤»
 
So, this looks good to me. Assigning to moritz++ for testing.

-- 
Will "Coke" Coleda