# New Ticket Created by "Mark E. Shoulson"
# Please include the string: [perl #103412]
# in the subject line of all future correspondence about this issue.
# <URL: https://rt.perl.org:443/rt3/Ticket/Display.html?id=103412 >
$ perl6 --version
This is perl6 version 2011.10-98-g1985138 built on parrot 3.9.0 revision
RELEASE_3_9_0-51-g65e6ab7
$ perl6
> "e u a u e u a" ~~ /:sigspace ("a") ([<[aeiou]> ]+)$/
=> < a u e u a>
0 => <a>
1 => <u e u a>
> "e u a u e u a" ~~ /:sigspace .("a") ([<[aeiou]> ]+)$/
#<failed match>
> # Only a single . was added before the ("a"), which is plainly not at the
> beginning of the line.
> "e u a u e u a" ~~ /:sigspace .?("a") ([<[aeiou]> ]+)$/
=> < a u e u a>
0 => <a>
1 => <u e u a>
> # OK, making the . optional works, but what if I try to capture it?
> "e u a u e u a" ~~ /:sigspace (.?)("a") ([<[aeiou]> ]+)$/
#<failed match>
> # Surely choosing to capture a part of the match shouldn't affect whether it
> matches at all!
This all works differently if we use a space between the . and the ("a"). It
looks like
at least some my own difficulty in the particular case relates to the space
after
the :sigspace adverb counting as whitespace, but does that explain everything?
~mark