[perl #117103] [BUG] (|)= doesn't parse in Rakudo

[Carl Mäsak]

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<masak> r: https://gist.github.com/masak/5124688
<p6eval> rakudo 5a6b52: OUTPUT«set(abcd, bacd, acbd, abdc, badc, adbc,
dabc, adcb, dacb, acdb, cadb, cdab, cabd, cbad, bcad, cbda, bcda,
cdba, dcba, dbca, dcab, bdca, dbac, bdac)␤»
<masak> \o/
<TimToady> masak: $set = $set (|) $d;  <-- why not (|)=  ?
<masak> TimToady: didn'a work :(
<masak> r: my $s = set; $s (|)= 5
<p6eval> rakudo 5a6b52: OUTPUT«===SORRY!===␤Two terms in a row␤at
/tmp/VbH2WyDu5i:1␤------> my $s = set; $s ⏏(|)= 5␤    [...]
* masak submits rakudobug
<TimToady> masak: you should get masak to file a...
<masak> TimToady: this time, I was faster than that guy! :P