I don't quite follow the unease from this example, but that's
probably because of the way that Perl 6 thinks of "undefined"
being different from Perl 5's "undef" and "defined".
In particular:
> ...
> sub array {
> my $what = shift;
> my $array = [];
> return $array if $what eq 'undef';
Perl 6 wouldn't treat C< my $array = []; > as having
any sort of "undefined" result -- it's absolutely
a defined Array (albeit empty). In Perl 6, the way
one would obtain an undefined array is with something
like
my $array = Array;
or
my @array; # rakudo currently gets this wrong,
# which is part of what brought up
# the discussion on #perl6 :-)
Or, put another way, in Perl 6 an undefined array
is denoted by its type object (just like most other
undefined values such as Int, Str, etc.).
Hope I've not just confused things even further.
Pm
