# New Ticket Created by Zefram # Please include the string: [perl #128965] # in the subject line of all future correspondence about this issue. # <URL: https://rt.perl.org/Ticket/Display.html?id=128965 >
If I construct a Pair whose key is a Scalar object, then the identity of that key object is not properly reflected in the .WHICH value of the Pair: > my $a = 3; my $b = Pair.new($a.VAR, "z"); say $b.WHICH; $a = 5; say $b.WHICH Pair|Int|3|Str|z Pair|Int|5|Str|z As you can see, the Pair.WHICH method is looking at the value inside the Scalar container. As a result, the .WHICH value of the single Pair object is changing over time, which should never happen. Pair.WHICH should be looking only at the identity of the Scalar itself. The correct .WHICH string would be something like "Pair|Scalar|47948211032816|Str|z". I believe the fix is for Pair.WHICH to apply .VAR to $!key. -zefram
