So that leaves nqp::pow_n(1e0, NaN) == 1e0. Is that also part of IEEE?
I see that Perl 5 gives a NaN for NaN**0, but 1 for 1**NaN:
zoffix@VirtualBox:~$ perl -wlE 'say -sin(9**9**9)**0'
NaN
zoffix@VirtualBox:~$ perl -wlE 'say 1**-sin(9**9**9)'
1
On Mon Oct 17 00:25:15 2016, barto...@gmx.de wrote:
> On Sun Oct 16 11:07:16 2016, alex.jakime...@gmail.com wrote:
> > Just for the record, another case:
> >
> > Code:
> > say NaN**0
> >
> > Output:
> > 1
>
> There was an earlier RT for this one (coming to the conclusion that 1
> is a reasonable answer here):
> https://rt.perl.org/Ticket/Display.html?id=124450. It has a link to a
> discussion from stackoverflow -- to me the following comment
> was interesting: http://stackoverflow.com/a/17865226
