# New Ticket Created by Sam S. # Please include the string: [perl #130859] # in the subject line of all future correspondence about this issue. # <URL: https://rt.perl.org/Ticket/Display.html?id=130859 >
A WhateverCode containing an array subscript that is itself a WhateverCode, usually works fine... e.g. `*.[*-1]` always returns the last positional element of its argument. A WhateverCode closing over a lexical variable usually works fine, e.g. `* - $x` always subtracts the *current* value of $x from its argument. But when *both* of those features are combined, *and* the variable that is closed over is scoped to an outer block or routine that is called repeatedly, then it misbehaves: sub f { my $x = ++$; (*.[* - $x])(<a b c>) } say (f,f,f); # (c c c) The same, using `map`: say (1..3).map: { (*.[* - $_])(<a b c>) }; # (c c c) The expected output would be `(c b a)`. For some reason, it seems to use the first value of `$x` or `$_` for all three iterations. ---------- Demonstration that the particular circumstances described above have to align for the bug to appear: 1) If the WhateverCode subscript is replaced with a static expression, the bug disappears: say (1..3).map: { (*.[3 - $_])(<a b c>) }; # (c b a) 2) If the outer WhateverCode is removed by "inlining" it, the bug disappears: say (1..3).map: { <a b c>[* - $_] }; # (c b a) 3) If the `map` is unrolled so that there is no outer block that gets re-entered between invocations of the WhateverCode's, the bug disappears: my &f = *.[* - $_]; $_ = 1; say f <a b c>; # c $_ = 2; say f <a b c>; # b $_ = 3; say f <a b c>; # a ---------- This is Rakudo version 2017.02-95-g0be724727 built on MoarVM version 2017.02-7-g3d859008 implementing Perl 6.c.