On Tue, Nov 22, 2005 at 09:32:37AM -0800, Chip Salzenberg wrote:
> On Tue, Nov 22, 2005 at 03:28:02PM +0100, Leopold Toetsch wrote:
> > sub do_add3 {
> > my $a = $_[0];
> > sub add3 {
> > $a + 3;
> > }
> > add3();
> > }
>
> What Perl 5 does with that case is just a plain old bug, or more
> precisely, a consequence of how Perl 5 implements capturing a lexical
> environment. It's just bad. Don't even try supporting it.
As the current "owner" of the perl5 closure code, (and as someone who
hasn't been following this thread :-( ), I'm interested to know what the
p6 semantics of this are. The p5 semantics seem to me to be logical and
consistent, if not particularly useful in this case: ie subs capture their
outside lexical scope at the time they are created. So at compile time,
add3() captures the first instance of do_add3()'s $a and hangs onto it for
dear life.
In p6, will $a remain shared between the two subs? In which case, at what
point is $a considered to have gone out of, or come into scope, from the
perspective of creating and destroying instances of lexicals variables?
Dave
--
Monto Blanco... scorchio!
