Okay, so this:
100 < -s $filepath <= 1e6
really means this:
100 < -s $filepath && -s $filepath <= 1e6
which means that this:
$a == $b != NaN
really means this:
$a == $b && $b != NaN
But "$a == $b != NaN" is supposed to "[solve] the problem of numerical
comparisons between non-numeric strings." Well, what if:
$a = 'hello';
$b = 0;
Doesn't that mean:
"hello" == 0 && 0 != NaN
will evaluate to true? Is that expected behavior for comparing
"hello" and 0 with the EQ operator? Or am I not getting the
purpose of the "$a == $b != NaN" idiom?
-John
