On 22 May 2002 at 13:10, Luke Palmer wrote:
> Since this is a Perl 6 list, here's how you would do it in Perl 6 (unless
> there's a better way):
>
> sub myint($x) { my $i = int $x; $i == $x ? $x : $i }
Shouldn't that be
sub myint($x) { my $i = int $x; $i == $x ?? $x :: $i }
as ?: operator is changed in Perl6.
--
Markus Laire 'malaire' <[EMAIL PROTECTED]>
