Luke Palmer:
# Wait, does this have any meaning?:
#
# my &half = \div(y => 2)
Call div() with the named parameter 'y' equal to 2, take a reference to
its return value, and store that in &half.
# Is backslash even a valid operator for reference anymore? If so, this
# makes sense to me.
I'm sure it's still there. Otherwise there's no way to take a reference
to a scalar.
--Brent Dax <[EMAIL PROTECTED]>
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