On Wed, Oct 30, 2002 at 11:26:01AM -0500, Buddha Buck wrote:
> How would you parse:
>
> @a = @b[[5]];
>
> (My intent: for @a; @b -> $x is rw; $y { $x = $y[5] }; # I think... )I'd write that as @a [=] @b[5]; -Scott -- Jonathan Scott Duff [EMAIL PROTECTED]
