When junctions collapse, is that reflected back in the original
junction, as it should be (QM-wise)?
$foo = 1 | 2 | 4
print $foo;
# Foo is now just one of (1, 2, 4); i.e. not a junction
If so, what is perl going to do about the computationally expensive
entanglement thingy?
$x = 0 | 1;
$y = 0 | 1;
$z = $x * $y;
print $z; # 0 with 0.75 probability and 1 with 0.25
# If 0 was printed, then $x | $y == 0
# If 1 was printed, then $x & $y == 1
Here, are $x and $y collapsed yet, or are they still in an entangled
superposition?
Luke
