... Let's take the first one first, because it is what S06 seems to imply, although it is against Perl5's tie() intuition:
my @carton is Scalar; # assuming this is the default
Now @carton implements the same set of behaviour as $spot. It essentially means that every variable is a scalar variable, and the only different of @carton vs $spot is that @carton applies list context to its right hand side in assignment and binding, while $spot applies scalar context.
I asked that before, and answer was:
On Tue, 30 Nov 2004 14:13:52 -0800, Larry Wall wrote: ... I think the only place they differ is in list context. @a always interpolates, and $a never does.
and everywhere else they would work the same. rather little difference to have different "namespaces", huh?
I still have some doubts. How could I make a reference to array? looks like this should work in perl6, because of scalar context: $arref = @arr; or the perl5 way. is it the same somehow? or is it wrong in perl6? $arref = [EMAIL PROTECTED];
and the mentioned problem is interesting too..
my @array is Scalar; # this isn't the default, as I know
@array = (1,2,3);
how such a weird var would behave?
my $var = "test";
my @arr := $var;
error? or maybe it would be the same weirdness, like in former example? or maybe it's a ["test"]?
