Luke Palmer <[EMAIL PROTECTED]> wrote:
> What is output:
> 
>     sub foo($x, ?$y, [EMAIL PROTECTED]) {
>         say "x = $x; y = $y; z = @z[]";
>     }
> 
>     my @a = (1,2,3);
>     foo($x, @a);

IANALarry, but I'd think

   x = ($x's value); y = 1 2 3; z = 

The $y is implicitly typed Any, and Ref of Array (or maybe just Array)
is consistent with Any; hence $y receives [EMAIL PROTECTED]

-- 
Brent 'Dax' Royal-Gordon <[EMAIL PROTECTED]>
Perl and Parrot hacker

"I used to have a life, but I liked mail-reading so much better."

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