On Wed, 2005-03-30 at 13:17, Thomas Sandlaß wrote: > HaloO Luke, > > you wrote: > > No, I think I agree with you here. But what happens if you change > > you're second-to-last line to: > > > > my $a = foo(); > > $a.meth() = 8; > > > > Perl 6 is both a statically typed language and a dynamically typed > > language, and the problems that I am addressing are mostly about the > > dynamic part. > > My state of affairs is that these two lines of code lack declarations > that clearly announce what the user of foo and X wanted: > 1) &foo returns an X
No, that was most of the point. &foo did not declare a return type, and while my code was simplistic, we obviously cannot be certain what &foo might return in the general case. Given that, Luke was making the point that $a had not explicit type. -- Aaron Sherman <[EMAIL PROTECTED]> Senior Systems Engineer and Toolsmith "It's the sound of a satellite saying, 'get me down!'" -Shriekback
