Luke Palmer <[EMAIL PROTECTED]> writes:
> On 7/26/05, Ingo Blechschmidt <[EMAIL PROTECTED]> wrote:
>> Hi,
>>
>> are the following assumptions correct?
>>
>> sub foo ([EMAIL PROTECTED]) { @args[0] }
>>
>> say ~foo("a", "b", "c"); # "a"
>
> Yep.
>
>> my @array = <a b c d>;
>> say ~foo(@array); # "a b c d" (or "a"?)
>> say ~foo(@array, "z"); # "a b c d" (or "a"?)
>
> "a" for both of these. The *@ area behaves just like Perl 5's calling
> conventions. I could argue for never auto flattening arrays, but then
> there'd really be no difference between @ and $.
>
>> say ~foo([EMAIL PROTECTED]); # "a"
>> say ~foo(*(@array, "z")); # "a"
>
> Hmm, *(@array, "z")... what does that mean? Whatever it means, you're
> correct in both of these. In the latter, the @array is in a
> flattening context, so it gets, well, flattened.
>
>> sub bar ([EMAIL PROTECTED]) { [EMAIL PROTECTED] }
>>
>> say bar(1,2,3); # 3
>> say bar(@array); # 1 (or 4?)
>
> 4
Wha? And I mean that sincerely. That's cockeyed. Surely a [EMAIL PROTECTED] in
the
signature simply says 'gather up the rest of the args and stick 'em in this
list'. In this case @array is a single argument, so @args should be equal to
[EMAIL PROTECTED] If I'm calling the function and I want @array to be treated as
anything but a single argument I use [EMAIL PROTECTED]
>> say bar(@array, "z"); # 2 (or 5?)
>
> 5
Double wha? That's even worse.
Do you claim that
say bar('z', @array)
also emits 5? Ick.
>> say bar([EMAIL PROTECTED]); # 4
>
> Yep.
So how *do* I pass an unflattened array to a function with a slurpy parameter?
