Ashley Winters skribis 2005-09-01 0:58 (-0700):
> If list construction is via the &infix:<,> operator, does that mean a
> blasphemous sinner could create &infix:<,=> as a synonym for push?
You could do that even without , being a list constructor.
However, in general, chained operators like comma, junction constructors
and infix zip, don't get an op= variant.
There's something nice in
$foo = 42;
$foo |= .bar for @quux;
as an alternative for
$foo = any 42, @quux>>.bar;
though
Juerd
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