On Fri, Oct 07, 2005 at 03:46:02PM -0600, Luke Palmer wrote:
> Uh no. Okay, when I said that they "don't close", I guess I meant
> they don't close like anonymous routines do. It works precisely like
> Perl 5's:
>
> sub foo {
> my $foo = 5;
> sub bar {
> return $foo;
> }
> return \&bar;
> }
>
> I don't think I've ever seen that used in Perl 5. Closing over that
> $foo doesn't mean anything.
Well strictly speaking it means that bar() captures the first instance of
foo()'s $foo, which isn't often very useful.
--
The Enterprise successfully ferries an alien VIP from one place to another
without serious incident.
-- Things That Never Happen in "Star Trek" #7
