On Fri, Jul 14, 2006 at 09:22:10 -0700, Dave Whipp wrote: > Darren Duncan wrote: > > >Assuming that all elements of $a and $b are themselves immutable to all > >levels of recursion, === then does a full deep copy like eqv. If at any > >level we get a mutable object, then at > >that point it turns into =:= (a trivial case) and stops. > > ( 1, "2.0", 3 ) === ( 1,2,3 ) > > True or false?
false > More imprtantly, how do I tell perl what I mean? The best I can think of is: > > [&&] (@a »==« @b) > Vs > [&&] (@a »eq« @b) Neither - it's on the natural types. If the types are different it's != -- Yuval Kogman <[EMAIL PROTECTED]> http://nothingmuch.woobling.org 0xEBD27418
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