On 8/8/06, Yuval Kogman <[EMAIL PROTECTED]> wrote:
On Tue, Aug 08, 2006 at 11:12:11 +0100, Daniel Hulme wrote:
> I may be in a little world of my own here, but isn't this what 'as' is
> supposed to do?
> foo($x as Moose);
as is a method invocation not a type annotation... It's related, but
not the same (last I heard)
Yep, in a perl5esque execution model, they should be the same thing,
but in a type-inferred environment they're two different things.
Assume such an environment:
my $x = Foo.new; # $x is a Foo
foo($x as Bar); # passed a Bar
foo($x); # passed a Foo
my $x = Foo.new; # coersed to Bar
foo($x :: Bar); # passed a Bar
foo($x); # passed a Bar
Which, needless to say, scares me a little. It is difficult to get
coersion and type inference to mix.