On 8/25/06, Michael Snoyman <[EMAIL PROTECTED]> wrote:
I asked this same question on perl6-users, but no one really seemed to have a definitive answer, so please forgive me for reasking.I was wondering how named arguments would work when parameters of different types had the same name, ie sub foo($bar, @bar, &bar) {...}.
That's probably an error at compile time, given the new provision that '@bar' => ... is not a named argument so we have no way to distinguish between the parameters. Luke
