Darren Duncan wrote: >> Perhaps, but then Junctions might not assume elements have equality or >> identity operations defined. >> > As I recall, every type in Perl 6 has an equality and identity > operation defined because the Object superclass provides one. If > nothing else, the type's equality and identity are the same as =:= > and .WHERE. >
Ok, seems reasonable. >> and that would >> also have the side effect of making creating a junction an O(N^2) operation. >> > Not if the type uses a hash-like index internally; then creating a > junction (or set) is more like O(N). > Oh, yes, good point. >> I think that the S06 definition needs re-wording. It's more like a Bag >> than a Set AIUI. >> > I don't know what part you are reading, but the list of types that I > see says that a Junction is "Sets with additional behaviours". > We're on the same page. It's just not the way that any of the prototypes have behaved to date. Sam.
