At 9:15 AM -0800 2/5/08, [EMAIL PROTECTED] wrote:
+The left side is evaluated completely for its sequence of containers before
+any assignment is done. Therefore this:
+
+ my $a = 0; my @b;
+ ($a, @b[$a]) = 1, 2;
+
+assigns 2 to @b[0], not @b[1].
Personally, I think this is a particularly welcome change.
For one thing, it is now possible to have defined, deterministic
semantics while freeing a compiler to auto-parallelize the list
assignment, as the container assignments themselves are now uncoupled.
-- Darren Duncan
