TSa Thomas.Sandlass-at-barco.com |Perl 6| wrote:
For functions, types don't need to be treated specially from other
arguments
as in C++.
Could you give an example of what you mean in C++ and how Perl differs
from that?
In C++, types are not first-class objects. You can't pass a type as a
normal parameter because there is no such thing.
So type parameters are treated differently with their own syntax:
foo<C,D>(x,y,z);
In Perl, you can simply pass
foo(::C, ::D, x, y, z);
because types are first-class objects. You can define parameters that
have a Type type, and use their value to create objects of that type,
and even annotate declarations.
--John
