split seems to be a suprisingly tricky beast ;-) To quote S29:
: As with Perl 5's split, if there is a capture in the pattern it : is returned in alternation with the split values. Unlike with : Perl 5, multiple such captures are returned in a single Match object. Unlike in Perl 5, it is not determined at (pattern) compile time if a regex has captures. In Perl 5 the regex m/(foo)?/ always has one capture ($1), in Perl 6 it has either zero or one ($0 doesn't exist if 'foo' never matched). So does split return the match objects * if the regex has the potential to create at least one capture or * at least one match actually produces a capture or * (weird) only those matches that produce a capture put a match object into the result list. I'd go for the first option. In that case it might be useful to have some sort of introspection, ie a method like $regex.has_capture (which might return either True (unconditional captures) or False (no captures at all) or True|False (for my example above) ;-) Cheers, Moritz -- Moritz Lenz http://moritz.faui2k3.org/ | http://perl-6.de/
