On 2009-Mar-17, at 2:16 am, Jon Lang wrote:
$choice.perl will return the same thing that the following would:
any($choice.eigenstates.«perl)
That is, it would return a Junction of Str, not a Str. So the
question is how to get something that returns an expression to the
effect of:
'any(' ~ $choice.eigenstates.«perl.join(',') ~ ')'
say $choice.perl
...which will ultimately call (junction-of-.perl's).Str, and
Str(Junction:) is what produces the "any(XXX)" string. [Unless it
ends up being implemented some other way, of course!]
The other question is: given $choice as defined above, how do I find
out which type of junction it is?
I guess really Junctions need two public methods: .eigenstates for the
values, and, er, .eigenop(?!) to return how they're joined -- I'm
thinking it would return a code ref, i.e. &any, &all, etc.
-David
