pugs-comm...@feather.perl6.nl wrote:
Author: moritz
Date: 2009-09-13 19:42:10 +0200 (Sun, 13 Sep 2009)
New Revision: 28233
Modified:
docs/Perl6/Spec/S03-operators.pod
Log:
[S03] ^4 cannot mean 0..3 and 0..^4 at the same time, because they are not the
same
The unary C<^> operator generates a range from C<0> up to
-one less than its argument. So C<^4> is short for C<0..^4> or C<0..3>.
+its argument, exclusively. So C<^4> is short for C<0..^4>.
for ^4 { say $_ } # 0, 1, 2, 3
I think that it would be better to pick the other meaning of C<^4> instead,
meaning C<0..3>, because that keeps the meaning of "^" consistent as "up to but
not including". Then also saying ^4 means you get a range of 4 elements, so
there is that consistency too.
Also, the code example still reflects the 0..3 meaning that I prefer, so it is
an error if the meaning you picked is chosen.
-- Darren Duncan
