Author: lwall
Date: 2009-12-15 22:14:10 +0100 (Tue, 15 Dec 2009)
New Revision: 29345
Modified:
docs/Perl6/Spec/S04-control.pod
Log:
[S04] remove fossilized restriction dug up by masak++
Modified: docs/Perl6/Spec/S04-control.pod
===================================================================
--- docs/Perl6/Spec/S04-control.pod 2009-12-15 19:08:43 UTC (rev 29344)
+++ docs/Perl6/Spec/S04-control.pod 2009-12-15 21:14:10 UTC (rev 29345)
@@ -13,8 +13,8 @@
Created: 19 Aug 2004
- Last Modified: 24 Nov 2009
- Version: 90
+ Last Modified: 15 Dec 2009
+ Version: 91
This document summarizes Apocalypse 4, which covers the block and
statement syntax of Perl.
@@ -221,22 +221,17 @@
my $x = sub { 3 }
my $x = sub { 3 };
-End-of-statement cannot occur within a bracketed expression, so
-this still works:
+Since bracketed expressions consider their insides to be statements,
+this works out consistently even where you might expect problems:
my $x = [
sub { 3 }, # this comma is not optional
- sub { 3 } # the statement won't terminate here
+ sub { 3 } # the statement inside [] terminates here
];
-However, a hash composer may never occur at the end of a line. If the
-parser sees anything that looks like a hash composer at the end of
-the line, it fails with "closing hash curly may not terminate line"
-or some such.
-
my $hash = {
1 => { 2 => 3, 4 => 5 }, # OK
- 2 => { 6 => 7, 8 => 9 } # ERROR
+ 2 => { 6 => 7, 8 => 9 } # OK, terminates inner statement
};
Because subroutine declarations are expressions, not statements,
