On Sat, Mar 13, 2010 at 08:53:02PM -0800, Darren Duncan wrote:
: Basically, I found this line in Synopsis 2, in the section talking about 
:     1+3\      i;
: So the question is about whether this example should be kept as
: still valid code or whether it is now invalid and a fossil?
: I suspect it *is* still valid, at least if this by itself:
:     3i
: ... is a valid literal denoting <0+3i>, but wanted to check.

Yes, both of those are still valid.  Thanks.

In fact, the \ is required if you want to use a variable:

    $foo + $bar\i

Well, I suppose you could also write that as:

    $foo + ($bar)i

but that could be construed as clunkier.  Or at least more typing.


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