Does ‘state’ govern ‘:=’ the way it governs ‘=’? In other words, just as this:
state $x = 1; only assigns to $x once (per closure), does the same apply to this? state $x := $y; I can’t find anything in the specs that implies that it does. The reason I ask is that I am currently implementing binding for Perl 5, but the syntax is different— \$x = \$y; (The reason for the different syntax is that, when we tried to use :=, we could not find a coherent way to handle edge cases [e.g., flattening vs not flattening]. Reusing existing Perl 5 syntax seemed the most straightforward and intuitive approach.) —and I am debating whether \state $x = \$y should bind only once or every time the surrounding code is executed. I could argue it either way (though I am leaning toward the latter), so I thought to find out what Perl 6 does.