> On 13 Oct 2015, at 17:15, Marc Chantreux <m...@unistra.fr> wrote: > > hello, > > playing with <>, two questions came to my mind: > > a) why isn't it "regular" ? > > use Test; > ok < foo bar bang > ~~ List, "a list"; > ok < foo bar > ~~ List, "a list"; > ok < foo > ~~ List, "a list"; diag "actually a Str"; > ok < > ~~ List, "a list"; > > not only it is an exception to a simple rule but it waste memorizable and > short > way to write a 1 element list. as always with perl6, i trust the perl6 > designers for having a very good reason and i'm curious: what is actually > this good reason for such a weird behave.
Well, for one, it is according to spec. :-) But the real reason, is that you can also use <a> to indicate the value of a key in a hash: my %h = a => 42; dd %h<a>; Now, you want that to return a single Int, not a List with one Int in it. So, that’s why <a> is a Str, and not a List. > b) shortest way to hash ? > > i used %(< class foo id bar >) in my code > > https://github.com/eiro/p6-Rototo/blob/master/t/basic.t#L21 > > i know it sounds stupid but i'm very sorry not being able to write (and most > of all: read and edit) > > %< class foo id bar > That is really a slice on an unnamed hash. So that is ambiguous. > > which isn't allowed ... but perl6 let me cheat: i can define a % > operator working with an extra space > > use v6; > use Rototo::html; > > sub H (*@data) { join '', @data } > sub prefix:<%> ( List $l ) is tighter(&infix:<,>) { %(|$l) } > > say % < id foo class bar >; # class => bar, id => foo > ( % < id foo class bar > ).^name.say; # Hash > say H br :id<foo>, :class<bar>; # <br id="foo" class="bar"/> > say H br |% < id foo class bar >; # <br id="foo" class="bar"/> > say H p |% < id foo class bar >, "this is a good thing”; > # <p id="foo" class="bar">this is a good thing</p> > > this is working but raised 2 questions: > > * if it was so easy, why isn't it in perl6? > [ ] i missed the good paragraph of the documentation ? > [ ] i'm going to do something very stupid ? > [ ] other, your answer here $ 6 'dd %(<a b c d>)’ Hash % = {:a("b"), :c("d")} > * i just don't know way i need | in front of % ... it just works but for > me %() was enought and explicit on what i wanted to get. can someone explain > ? I guess without the |, you would pass a Hash to br. With the |, it became a list of pairs. Can’t really tell without the br code. But, fwiw, I don’t think you need the prefix % at all :-) Liz
