in https://docs.perl6.org/type/Int#routine_expmod
it reads: routine expmod <https://docs.perl6.org/type/Int#___top> multi sub expmod(Int $y,Int $mod)returns Int:D multi method expmod(Int:D: Int $y,Int $mod)returns Int:D Returns the given |Int| raised to the |$y| power within modulus |$mod|. say expmod(4,2,5);# 1 say 7.expmod(2,5);# 4 Shouldn't the su form read: multi sub expmod(Int:D $x,Int $y,Int $mod)returns Int:D it needs three parameters -- .~. In my life God comes first.... /V\ but Linux is pretty high after that :-D /( )\ Francis (Grizzly) Smit ^^-^^ http://www.smit.id.au/ -----BEGIN GEEK CODE BLOCK----- Version: 3.1 GM/CS/H/P/S/IT/L d- s+:+ a++ C++++ UL++++$ P+++ L+++$ E--- W+++ N w--- M-- V-- PE- PGP t+ 5-- X-- R- tv b++++ DI(+) D- G e++ h+ y? r% z--- ------END GEEK CODE BLOCK------ http://www.geekcode.com/
