On Sun, Jun 3, 2018 at 6:22 PM ToddAndMargo <toddandma...@zoho.com <mailto:toddandma...@zoho.com>> wrote:

    On 06/03/2018 03:07 PM, Brandon Allbery wrote:
     > I'm still trying to figure out why you have just "lib" instead of
     > lib" there. And why it's not throwing an error.

    As poop!   I was mixing Perl 5 and Perl 6.

    $ p6 'use lib <./>; use RunNoShell; ( my $a, my $b ) =
    say $a;'



    $ p6 'use lib <./>; use RunNoShell; ( my $a, my $b ) =
    RunNoShell::RunNoShell("ls6"); say $a;'
    Could not find symbol '&RunNoShell'
        in block <unit> at -e line 1

    The syntax `RunNoShell::RunNoShell` comes from Perl 5.  Is this
    not allows in Perl 6?

On 06/03/2018 03:24 PM, Brandon Allbery wrote:
It is allowed if you have 'unit module RunNoShell;' at the top of RunNoShell.pm6. Otherwise you defined it in the main namespace and looking for it in the RunNoShell namespace will fail.

Perl 5 does the same thing fi you omitted 'package RunNoShell;' at the top of RunNoShell.pm.

The name of the file is `RunNoShell.pm`

It has two exported subs:
     sub RunNoShellErr ( $RunString ) is export
     sub RunNoShell ( $RunString ) is export

If I place
     unit module RunNoShell;

at the top, what happens?
    All subs get exported?
    Do I have to import them differently

           Old way:
               use RunNoShell;  # qx[ RunNoShell ];

Reply via email to