It is "do G=" not "do $G="
On 08/04/2018 01:14 AM, Laurent Rosenfeld via perl6-users wrote:
I'm really not very good at bash scripting (because I would almost always to such things in Perl), but I guess that the initial $G is an error (there should not be a $ sigil).
That was it. Perl has got me so trained that I did not even realize my mistake for quite some time. Chuckle
