In that case, you're not giving it two items; you are giving it a single List that happens to have two items within it. A method has one invocant. If you are invoking method foo on that, its invocant is a List.
> my $a; my $b; say ($a, $b).^name List On Fri, Sep 14, 2018 at 6:47 PM ToddAndMargo <toddandma...@zoho.com> wrote: > Hi All, > > Can a method be given multiple inputs? > > ( $a, $b ).foo > > and how would the docs write it? > > method foo(Any:D Any:D: -->Bool) > > Is there a comma or a space between the two "any"'s? > > Many thanks, > -T > -- brandon s allbery kf8nh allber...@gmail.com