You can't with that, because < ... > acts like single quotes; '@x' there is
a string literal, not the list @x. If you use << ... >> then it act like
double quotes, and will use the list instead.
On Fri, Oct 5, 2018 at 9:23 PM ToddAndMargo via perl6-users <
perl6-users@perl.org> wrote:
> On 10/5/18 6:09 PM, Brandon Allbery wrote:
> > That's where the | comes in. If you say
> >
> > my @b = (1, |@a, 2);
> >
> > then you get (1, 'a', 'b', 'c', 2) like in Perl 5. But you can specify
> > what gets flattened, so you can choose to flatten some arrays but not
> > others if you need to for some reason:
> >
> > my @b = (1, |@b, 2, @b, 3);
> >
> > gives you (1, 'a', 'b', 'c', 2, ('a', 'b', 'c'), 3). This often matters
> > in parameter lists, if you want one of the parameters to be the list
> > itself instead of it being spread across multiple parameters. In Perl 5
> > you had to say \@b to pass a ref to the list instead, and the sub had to
> > know it was getting a scalar containing an arrayref and needed to
> > dereference it (if you don't know, don't ask; it's ugly).
>
> Am I correct in my assumption?
>
> A little off the question, but how do I address something
> inside a nested array?
>
> In the following, how do I get at the "b"
>
>
> $ p6 'my @x=<a b c>; my @y=<1 2 @x 3 4>; say @y; dd @y;'
>
> [1 2 @x 3 4]
>
> Array @y = [IntStr.new(1, "1"), IntStr.new(2, "2"), "\@x", IntStr.new(3,
> "3"), IntStr.new(4, "4")]
>
> Also, how do I flatten @y above?
>
> Thank you for the help!
> -T
>
--
brandon s allbery kf8nh
allber...@gmail.com
