El sáb., 6 oct. 2018 a las 1:17, Timo Paulssen (<t...@wakelift.de>) escribió:
> Yes, there is an absolutely tiny mention of it on the page: > > Metaoperators > > Metaoperators can be parameterized with other operators or subroutines in > the same way as functions can take functions as parameters. To use a > subroutine as a parameter, prefix its name with a &. Perl 6 will generate > the actual combined operator in the background, allowing the mechanism to > be applied to user defined operators. *To disambiguate chained > metaoperators, enclose the inner operator in square brackets.* There are > quite a few metaoperators with different semantics as explained, next. > If that's even the part you're asking about, that is. And yes, I would > consider that LTA, making it easier to find, for example by adding an > example or maybe even a sub-heading, would be really good. Who wants to > open a ticket? :) > Please someone do that. I'm kind of lost among all the long thread, and I might be wrong about the intention. JJ
