On 12/20/18 2:49 PM, Laurent Rosenfeld via perl6-users wrote:
$D0 = ~$0; $D1 = ~$1; # ...
Hi Laurent, Except that it crashed in "perl6 -e", which is where I do all my syntax testing. Is okay, Perl was 101 ways of doing everything, so I can still "get 'er done". I also instantly recognize .Str when I look at it. What initially confused me was thinking that the match would take on the type of what it matched. (<\N>+) would look for number like characters, so a string and (\d+) would look for digits, so an integer. Woops! Good thing I asked. Thank you for all the help! -T
