Fixed with https://github.com/rakudo/rakudo/commit/23663609a7
> On 27 Dec 2018, at 09:29, Raymond Dresens <raymond.dres...@gmail.com> wrote:
>
> Hello,
>
> I'm getting up to speed with Perl 6 again after a long while, and I more
> or less 'hit my nose' against something that I can reduce to the
> following very basic snippet of code:
>
> my $foo = 3;
> say $foo;
>
> {
> say $foo;
>
> my $foo = 6;
>
> say $foo;
> }
>
> This will not compile with Perl 6 (Rakudo 2018.12) -- lexical symbol
> '$foo' is already bound to an outer symbol; the implicit outer binding
> must be rewritten as OUTER::<$foo> before you can unambiguously declare
> a new '$foo' in this scope.
>
> This will compile with Perl 5 when I add 'use v5.14;' at the top and it
> will then print 3, then 3 then 6 (as expected).
>
> Well, it seems that I can 'cheat' by simply doing a list assignment:
>
> my $foo = 3;
> say $foo;
>
> {
> say $foo;
>
> my ($foo) = 6; # avoid `... '$foo' is already bound ...'
>
> say $foo;
> say $foo.WHAT; # is it really an integer?
> }
>
> The output is:
>
> 3
> (Any)
> 6
> (Int)
>
> This behavior is fine I think (but a little unexpected due to my
> experience with Perl 5).
>
> Is this behavior normal/wanted/intented (from a language/compiler
> perspective?).
>
> Perhaps this shouldn't be and the compiler should also complain in this
> list assignment case, or perhaps generate a warning?
>
> I'm not that confident to state that this is a bug ;)
>
> Hence the reason why I kind-of report this,
>
> I hope this is somewhat useful,
>
> Thanks for your time,
>
> Regards,
>
> Raymond Dresens.
