Hello,
This seems possible:
> my @x = (1, 2, 3, 4, 8, 16, 32, 64, 128);
[1 2 3 4 8 16 32 64 128]
Then:
> for @x -> $x, $y, $z { $x.say }
1
4
32
And:
> for @x -> $x, Any, Any { $x.say }
1
4
32
...assigning to 'Any' seems to 'just work'. Assigning to 'Nil' didn't work,
however.
Is this what you are looking for?
Perhaps there's a better way for doing this? If so, I'd like to know too :)
Regards,
Raymond.
On Sat, 23 Nov 2019 at 07:00, ToddAndMargo via perl6-users <
[email protected]> wrote:
> Hi All,
>
> In a "for" loop, what is the syntax for "by 3"?
>
> for @x.lines by 3
>
> In other words, every third line.
>
> Many thanks,
> -T
>
