On Sun, 19 Apr 2020, yary wrote: > Question from today's Raku meetup. This works in a way I expect > > > 'fosdffgg'.subst(/f+/,"( "~ * ~" )", :g); > ( f )osd( ff )gg > > This one, $0 gets the single f each time > > > 'fosdffgg'.subst(/(f+)/,"( $0 )", :g); > ( f )osd( f )gg > > Bug or misunderstanding on my part? >
Not a bug. You are calling the subst method on a string. Naturally, in order to perform the call, all the arguments you pass have to be evaluated first. This includes interpolating $0 into the string "( $0 )". You take whatever $0 contains, put it into a string and pass that into subst. In your case $0 seemed to confusingly stringify to "f". Consider this instead: "oops" ~~ /^(..)/ andthen say 'fosdffgg'.subst(/(f+)/,"( $0 )", :g) # OUTPUT: «( oo )osd( oo )gg» where I deliberately set $0 beforehand. Your first variant works because you pass a Callable into subst and when you do that subst will repeatedly evaluate the Callable. Not so when you pass a string value. Regards, Tobias -- "There's an old saying: Don't change anything... ever!" -- Mr. Monk
