http://perldoc.perl.org/functions/time.html

time Perl functions A-Z <http://perldoc.perl.org/index-functions.html> | Perl
functions by category
<http://perldoc.perl.org/index-functions-by-cat.html>| The
'perlfunc' manpage <http://perldoc.perl.org/perlfunc.html>

   - *time*

    Returns the number of non-leap seconds since whatever time the system
   considers to be the epoch, suitable for feeding to
gmtime<http://perldoc.perl.org/functions/gmtime.html>and
   localtime <http://perldoc.perl.org/functions/localtime.html>. On most
   systems the epoch is 00:00:00 UTC, January 1, 1970; a prominent exception
   being Mac OS Classic which uses 00:00:00, January 1, 1904 in the current
   local time zone for its epoch.

   For measuring time in better granularity than one second, you may use
   either the Time::HiRes <http://perldoc.perl.org/Time/HiRes.html> module
   (from CPAN, and starting from Perl 5.8 part of the standard distribution),
   or if you have gettimeofday(2), you may be able to use the
syscall<http://perldoc.perl.org/functions/syscall.html>interface of
Perl. See
   perlfaq8 <http://perldoc.perl.org/perlfaq8.html> for details.

   For date and time processing look at the many related modules on CPAN.
   For a comprehensive date and time representation look at the
DateTime<http://search.cpan.org/perldoc/DateTime>module.


----------------------------------
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2009/9/15 Uliyas Fan <[email protected]>

> 如果我想得到一个指定时间到1970-1-1日的秒数,应该有什么办法? 比分说想知道2003-5-7 13:50:06 到1970-1-1
> 00:00:00的秒数。
> 谢谢
>
> >
>

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