this looks like a big patch because i removed the comment characters before
the bulk of the text. Russ's explanation doesn't need to be code comments.
* other changes
+ removed the flame-war bait about localtime() - 86400. everywhere
i saw someone discuss that solution people starting flaming each other over
all sorts of stuff, so i don't think it is a good thing to tell newbies to do. i
also do not like to start off answers with a wrong answer.
+ start off with a module solution
Index: perlfaq4.pod
===================================================================
RCS file: /cvs/public/perlfaq/perlfaq4.pod,v
retrieving revision 1.34
diff -u -d -r1.34 perlfaq4.pod
--- perlfaq4.pod 23 Oct 2002 01:00:37 -0000 1.34
+++ perlfaq4.pod 24 Oct 2002 19:58:27 -0000
@@ -449,58 +449,60 @@
=head2 How do I find yesterday's date?
-The C<time()> function returns the current time in seconds since the
-epoch. Take twenty-four hours off that:
-
- $yesterday = time() - ( 24 * 60 * 60 );
+If you only need to find the date (and not the same time), you
+can use the Date::Calc module.
-Then you can pass this to C<localtime()> and get the individual year,
-month, day, hour, minute, seconds values.
+ use Date::Calc qw(Today Add_Delta_Days);
+
+ my @date = Add_Delta_Days( Today(), -1 );
+
+ print "@date\n";
-Note very carefully that the code above assumes that your days are
-twenty-four hours each. For most people, there are two days a year
-when they aren't: the switch to and from summer time throws this off.
-A solution to this issue is offered by Russ Allbery.
+Most people try to use the time rather than the calendar to
+figure out dates, but that assumes that your days are
+twenty-four hours each. For most people, there are two days
+a year when they aren't: the switch to and from summer time
+throws this off. Russ Allbery offers this solution.
sub yesterday {
- my $now = defined $_[0] ? $_[0] : time;
- my $then = $now - 60 * 60 * 24;
- my $ndst = (localtime $now)[8] > 0;
- my $tdst = (localtime $then)[8] > 0;
- $then - ($tdst - $ndst) * 60 * 60;
- }
- # Should give you "this time yesterday" in seconds since epoch relative to
- # the first argument or the current time if no argument is given and
- # suitable for passing to localtime or whatever else you need to do with
- # it. $ndst is whether we're currently in daylight savings time; $tdst is
- # whether the point 24 hours ago was in daylight savings time. If $tdst
- # and $ndst are the same, a boundary wasn't crossed, and the correction
- # will subtract 0. If $tdst is 1 and $ndst is 0, subtract an hour more
- # from yesterday's time since we gained an extra hour while going off
- # daylight savings time. If $tdst is 0 and $ndst is 1, subtract a
- # negative hour (add an hour) to yesterday's time since we lost an hour.
- #
- # All of this is because during those days when one switches off or onto
- # DST, a "day" isn't 24 hours long; it's either 23 or 25.
- #
- # The explicit settings of $ndst and $tdst are necessary because localtime
- # only says it returns the system tm struct, and the system tm struct at
- # least on Solaris doesn't guarantee any particular positive value (like,
- # say, 1) for isdst, just a positive value. And that value can
- # potentially be negative, if DST information isn't available (this sub
- # just treats those cases like no DST).
- #
- # Note that between 2am and 3am on the day after the time zone switches
- # off daylight savings time, the exact hour of "yesterday" corresponding
- # to the current hour is not clearly defined. Note also that if used
- # between 2am and 3am the day after the change to daylight savings time,
- # the result will be between 3am and 4am of the previous day; it's
- # arguable whether this is correct.
- #
- # This sub does not attempt to deal with leap seconds (most things don't).
- #
- # Copyright relinquished 1999 by Russ Allbery <[EMAIL PROTECTED]>
- # This code is in the public domain
+ my $now = defined $_[0] ? $_[0] : time;
+ my $then = $now - 60 * 60 * 24;
+ my $ndst = (localtime $now)[8] > 0;
+ my $tdst = (localtime $then)[8] > 0;
+ $then - ($tdst - $ndst) * 60 * 60;
+ }
+
+Should give you "this time yesterday" in seconds since epoch relative to
+the first argument or the current time if no argument is given and
+suitable for passing to localtime or whatever else you need to do with
+it. $ndst is whether we're currently in daylight savings time; $tdst is
+whether the point 24 hours ago was in daylight savings time. If $tdst
+and $ndst are the same, a boundary wasn't crossed, and the correction
+will subtract 0. If $tdst is 1 and $ndst is 0, subtract an hour more
+from yesterday's time since we gained an extra hour while going off
+daylight savings time. If $tdst is 0 and $ndst is 1, subtract a
+negative hour (add an hour) to yesterday's time since we lost an hour.
+
+All of this is because during those days when one switches off or onto
+DST, a "day" isn't 24 hours long; it's either 23 or 25.
+
+The explicit settings of $ndst and $tdst are necessary because localtime
+only says it returns the system tm struct, and the system tm struct at
+least on Solaris doesn't guarantee any particular positive value (like,
+say, 1) for isdst, just a positive value. And that value can
+potentially be negative, if DST information isn't available (this sub
+just treats those cases like no DST).
+
+Note that between 2am and 3am on the day after the time zone switches
+off daylight savings time, the exact hour of "yesterday" corresponding
+to the current hour is not clearly defined. Note also that if used
+between 2am and 3am the day after the change to daylight savings time,
+the result will be between 3am and 4am of the previous day; it's
+arguable whether this is correct.
+
+This sub does not attempt to deal with leap seconds (most things don't).
+
+
=head2 Does Perl have a Year 2000 problem? Is Perl Y2K compliant?
