On Thu, Apr 28, 2011 at 15:41, ilyas ilyas <ilyascfd at gmail.com> wrote:
> Would you please explain more the first option? You create a system with larger block size. If you have two node-centered values and one cell-centered, you would use a block size of 3. Each center would be associated with the node to its lower left, for example. There will be a fringe of "cell-centers" that extend out of domain on the right and top, you use x = 0 for these equations and the Jacobian for those equations will just have a 1 on the diagonal. -------------- next part -------------- An HTML attachment was scrubbed... URL: <http://lists.mcs.anl.gov/pipermail/petsc-users/attachments/20110428/c2b9bbdd/attachment.htm>
